Shoes+Shoes+Shoes=30\text{Shoes} + \text{Shoes} + \text{Shoes} = 30Shoes+Shoes+Shoes=30This implies each pair of shoes is 101010:
10+10+10=3010 + 10 + 10 = 3010+10+10=30Second equation:
Boy+Boy+Shoes=20\text{Boy} + \text{Boy} + \text{Shoes} = 20Boy+Boy+Shoes=20Since the shoes are 101010, we have:
2×Boy+10=202 \times \text{Boy} + 10 = 202×Boy+10=20Solving for the boy:
2×Boy=10⇒Boy=52 \times \text{Boy} = 10 \Rightarrow \text{Boy} = 52×Boy=10⇒Boy=5Third equation:Burger+Burger+Boy=13\text{Burger} + \text{Burger} + \text{Boy} = 13Burger+Burger+Boy=13We know the boy is 555, so:
2×Burger+5=132 \times \text{Burger} + 5 = 132×Burger+5=13Solving for the burger:
2×Burger=8⇒Burger=42 \times \text{Burger} = 8 \Rightarrow \text{Burger} = 42×Burger=8⇒Burger=4Final equation:
Shoe+(Boy with two small burgers)×Burger=?\text{Shoe} + (\text{Boy with two small burgers}) \times \text{Burger} = ?Shoe+(Boy with two small burgers)×Burger=? A single shoe is half of a pair, so it’s 555. The boy with two small burgers should represent 5+2=75 + 2 = 75+2=7. The burger is 444.Now, substitute into the equation:
5+(7×4)=5+28=335 + (7 \times 4) = 5 + 28 = 335+(7×4)=5+28=33Answer: 33
Leave a Reply